I am a two digit number. I am equal to the sum of my digits multiplied by six. What number am I?

Write out the 6 times table until you find the answer that meets the criteria

54 (5 + 4 = 9, 9 x 6 =54)

Prices went up by 2% in 2003, 3% in 2004 and 2.5% in 2005.

If an item cost £32 at the start of 2003 what would it cost at the end of 2005?

From "Foundation GCSE Mathematics For WJEC: Homework Book"

Remember: The total from which you are calculating the percentage will change after each year.

Start with £32

In 2003 the price goes up to:

32 + (32 ÷ 100 x 2) = £32.64

In 2004 the price goes up to:

32.64 + (32.64 ÷ 100 x 3) =£33.62 (nearest penny)

In 2005 the price goes up to:

33.62 + (33.62 ÷ 100 x 2.5) = £34.46 (nearest penny)

Excel version of number search for screen readers

*Find the below numbers in the grid.
The numbers can be in any direction: backwards, forwards, up, down, or diagonally.*

128036 | 438795 | 638358 |

132798 | 456405 | 658582 |

170596 | 466855 | 689972 |

247495 | 473829 | 782657 |

257669 | 488671 | 826867 |

274797 | 489151 | 855033 |

376203 | 524548 | 865664 |

389980 | 606563 | 868369 |

400950 | 608607 | 954445 |

414663 | 626528 | 989895 |

From www.puzzles-to-print.com

Dafydd is late 60% of the time when it is raining and 30% of the time when it is dry. it rains on 25% of days.

Find the probability that:

- It is raining and he is late
- He is late

Adapted from "Higher GCSE Maths" by Michael White

Consider using a probability tree to help with this. More information on probability tree diagrams can be found at the Maths is Fun website.

The resultant probability tree:

- Raining and late

probability = 0.25 x 0.6 = 0.15 or 15% - Late

probability = (0.25 x 0.6) + (0.75 x 0.3) = 0.375 or 37.5%

A group of fifty soldiers suffered the following injuries in battle:

- 36 lost an eye,
- 35 lost an ear,
- 40 lost a leg
- 42 lost an arm

*What is the minimum number of soldiers to suffer all four injuries?*

Adapted from: "Einstein's Riddle" by Jeremy Stangroom

Consider the total number of injuries compared to the total number of soldiers.

Total number of injuries = 36 + 35 + 40 + 42 = 153

Total number of soldiers = 50

150 ÷ 50 = 3 with a remainder of 3.

Therefore, a minimum of three soldiers had all four injuries.